Air Canada AC2005 Flight Status Today

International flight Air Canada AC2005 takes off from Kingston (KIN) Jamaica to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Norman Manley International Airport at 15:30 America/Jamaica. The flight is expected to land at Pearson International Airport at 19:45 America/Toronto. The flight will last about 4 hours 15 minutes.

AC2005 - ACA2005 Air Canada (AC)
KIN Kingston Jamaica
Flight KIN to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Norman Manley International Airport
IATA: KINICAO: MKJP
Scheduled 15:30
None None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 19:45
1 F63
AC2005 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 15 minutes
  • Flight Distance: 2867 kms / 1781 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A321
  • Callsign: None
  • Departure Timezone: America/Jamaica
  • Arrival Timezone: America/Toronto
  • Current Time in Kingston: Monday 2026-03-02 09:15 AM
  • Current Time in Toronto: Monday 2026-03-02 09:15 AM

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Air Canada Flight AC2005 FAQs

What is the scheduled flight duration for Air Canada AC2005 flight?

On average, nonstop flight takes 4 hour(s) 15 minutes, with the flight distance of 2867 km (1781 miles).

What type of aircraft is used for the Air Canada AC2005 flight?

All Air Canada AC2005 flights are operated using Airbus A321 aircraft.

Which terminal the flight Air Canada AC2005 is arriving at?

Flight Air Canada AC2005 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC2005 flights are operated a week?

6 flights per week. The Flight Air Canada AC2005 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Sunday.