Air Canada AC1805 Flight Status Today

International flight Air Canada AC1805 takes off from Montego Bay (MBJ) Jamaica to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves Sangster International Airport at 12:10 America/Jamaica. The flight is expected to land at Pearson International Airport at 17:20 America/Toronto. The flight will last about 3 hours 58 minutes.

AC1805 - ACA1805 Air Canada (AC)
MBJ Montego Bay Jamaica
Flight MBJ to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure Sangster International Airport
IATA: MBJICAO: MKJS
Scheduled 12:10
None 18
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 17:20
1 None
AC1805 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 58 minutes
  • Flight Distance: 2797 kms / 1738 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Monday
Passenger Services
  • Service type: Normal passenger
  • Seats: 208
  • Freight capacity: 14.4 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A321 (sharklets)
  • Callsign: ROU1805
  • Departure Timezone: America/Jamaica
  • Arrival Timezone: America/Toronto
  • Current Time in Montego Bay: Monday 2025-12-29 18:18 PM
  • Current Time in Toronto: Monday 2025-12-29 18:18 PM

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Air Canada Flight AC1805 FAQs

What is the scheduled flight duration for Air Canada AC1805 flight?

On average, nonstop flight takes 3 hour(s) 58 minutes, with the flight distance of 2797 km (1738 miles).

What type of aircraft is used for the Air Canada AC1805 flight?

All Air Canada AC1805 flights are operated using Airbus A321 (sharklets) aircraft.

Which terminal the flight Air Canada AC1805 is arriving at?

Flight Air Canada AC1805 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC1805 flights are operated a week?

1 flights per week. The Flight Air Canada AC1805 is operated on Monday.