Air Canada AC1802 Flight Status Today

International flight Air Canada AC1802 takes off from Toronto (YYZ) Canada to Kingston (KIN) Jamaica. It's operated by Air Canada. The plane leaves Pearson International Airport at 09:15 America/Toronto. The flight is expected to land at Norman Manley International Airport at 13:35 America/Jamaica. The flight will last about 4 hours 20 minutes.

AC1802 - ACA1802 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to KIN
KIN Kingston Jamaica
Contact Airlines It may not operate on the date requested
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 09:15
1 E81
Arrival Norman Manley International Airport
IATA: KINICAO: MKJP
Scheduled 13:35
None None
AC1802 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 20 minutes
  • Flight Distance: 2867 kms / 1781 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Friday
Passenger Services
  • Service type: Normal passenger
  • Seats: 120
  • Freight capacity: 1.6 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Airbus A321 (sharklets)
  • Callsign: ROU1802
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/Jamaica
  • Current Time in Toronto: Wednesday 2026-01-21 02:46 AM
  • Current Time in Kingston: Wednesday 2026-01-21 02:46 AM

Flight routes similar to Air Canada AC1802

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WestJet WS2480
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Air Canada Flight AC1802 FAQs

What is the scheduled flight duration for Air Canada AC1802 flight?

On average, nonstop flight takes 4 hour(s) 20 minutes, with the flight distance of 2867 km (1781 miles).

What type of aircraft is used for the Air Canada AC1802 flight?

All Air Canada AC1802 flights are operated using Airbus A321 (sharklets) aircraft.

How many Air Canada AC1802 flights are operated a week?

1 flights per week. The Flight Air Canada AC1802 is operated on Friday.