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American Airlines AA9974 Flight Status Today
Domestic flight American Airlines AA9974 takes off from Albany (ALB) United States to Akron (CAK) United States. It's operated by American Airlines. The plane leaves Albany International Airport at 16:00 30 December 2025 America/New_York. The flight is expected to land at Akron-Canton Airport at 17:00 30 December 2025 America/New_York. The flight will last about 60 minutes.
Current status of AA9974 is Unknown
- Type: Domestic Flight
- Flight Duration: 60 minutes
- Flight Distance: 665 kms / 413 miles
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: Monday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Canadair (Bombardier) Regional Jet 700 and Challenger 870
- Callsign: F-KEKX1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Albany: Tuesday 2025-12-30 15:39 PM
- Current Time in Akron: Tuesday 2025-12-30 15:39 PM
American Airlines Flight AA9974 FAQs
What is the scheduled flight duration for American Airlines AA9974 flight?
On average, nonstop flight takes 60 minutes, with the flight distance of 665 km (413 miles).
What is the current status of American Airlines AA9974 flight?
The current status of flight American Airlines AA9974 is Unknown.
What type of aircraft is used for the American Airlines AA9974 flight?
All American Airlines AA9974 flights are operated using Canadair (Bombardier) Regional Jet 700 and Challenger 870 aircraft.
When does the flight American Airlines AA9974 arrive?
Flight American Airlines AA9974 arrives at 17:00.
Which terminal the flight American Airlines AA9974 is arriving at?
Flight American Airlines AA9974 arrives in Akron-Canton Airport at Terminal -.
How many American Airlines AA9974 flights are operated a week?
2 flights per week. The Flight American Airlines AA9974 is operated on Monday, Sunday.
