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American Airlines AA9944 Flight Status Today
Domestic flight American Airlines AA9944 takes off from Cleveland (CLE) United States to Greenville (GSP) United States. It's operated by American Airlines. The plane leaves Cleveland Hopkins International Airport at 15:00 America/New_York. The flight is expected to land at Greenville-Spartanburg International Airport at 17:00 America/New_York. The flight will last about 0 minutes.
AA9944 - AAL9944
American Airlines (AA)
CLE
Cleveland United States
GSP
Greenville United States
Contact Airlines
It may not operate on the date requested
AA9944 Detail
- Type: Domestic Flight
- Flight Duration: 0 minutes
- Flight Distance: 725 kms / 450 miles
Airline
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: Wednesday, Friday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Embraer 175
- Callsign: F-KHEF3
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Cleveland: Sunday 2026-02-15 23:13 PM
- Current Time in Greenville: Sunday 2026-02-15 23:13 PM
Flight routes similar to American Airlines AA9944
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
AA9776 American Airlines |
15/02/2026 18:00 |
1 hours 30 minutes 19:30 |
American Airlines Flight AA9944 FAQs
What is the scheduled flight duration for American Airlines AA9944 flight?
On average, nonstop flight takes 0 minutes, with the flight distance of 725 km (450 miles).
What type of aircraft is used for the American Airlines AA9944 flight?
All American Airlines AA9944 flights are operated using Embraer 175 aircraft.
How many American Airlines AA9944 flights are operated a week?
2 flights per week. The Flight American Airlines AA9944 is operated on Wednesday, Friday.