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American Airlines AA9880 Flight Status Today
Domestic flight American Airlines AA9880 takes off from Kalamazoo (AZO) United States to Marquette (MQT) United States. It's operated by American Airlines. The plane leaves Kalamazoo/Battle Creek International Airport at 12:45 21 January 2026 America/New_York. The flight is expected to land at Sawyer International Airport at 15:40 21 January 2026 America/New_York. The flight will last about 1 hours 40 minutes.
Current status of AA9880 is Arrived On time
- Type: Domestic Flight
- Flight Duration: 1 hours 40 minutes
- Flight Distance: 480 kms / 298 miles
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: Monday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Embraer 175
- Callsign: N/A
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Kalamazoo: Wednesday 2026-01-21 20:44 PM
- Current Time in Marquette: Wednesday 2026-01-21 20:44 PM
American Airlines Flight AA9880 FAQs
What is the scheduled flight duration for American Airlines AA9880 flight?
On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 480 km (298 miles).
What is the current status of American Airlines AA9880 flight?
The current status of flight American Airlines AA9880 is Arrived On time.
What type of aircraft is used for the American Airlines AA9880 flight?
All American Airlines AA9880 flights are operated using Embraer 175 aircraft.
When does the flight American Airlines AA9880 arrive?
Flight American Airlines AA9880 arrives at 15:40.
Which terminal the flight American Airlines AA9880 is arriving at?
Flight American Airlines AA9880 arrives in Sawyer International Airport at Terminal B.
How many American Airlines AA9880 flights are operated a week?
1 flights per week. The Flight American Airlines AA9880 is operated on Monday.
