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American Airlines AA9800 Flight Status Today
Domestic flight American Airlines AA9800 takes off from Philadelphia (PHL) United States to New York (JFK) United States. It's operated by American Airlines. The plane leaves Philadelphia International Airport at 16:00 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 16:50 America/New_York. The flight will last about 0 minutes.
- Type: Domestic Flight
- Flight Duration: 0 minutes
- Flight Distance: 150 kms / 93 miles
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Boeing 787-9
- Callsign: F-KOKC1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Philadelphia: Saturday 2026-04-04 00:36 AM
- Current Time in New York: Saturday 2026-04-04 00:36 AM
American Airlines Flight AA9800 FAQs
What is the scheduled flight duration for American Airlines AA9800 flight?
On average, nonstop flight takes 0 minutes, with the flight distance of 150 km (93 miles).
What type of aircraft is used for the American Airlines AA9800 flight?
All American Airlines AA9800 flights are operated using Boeing 787-9 aircraft.
Which terminal the flight American Airlines AA9800 is arriving at?
Flight American Airlines AA9800 arrives in John F. Kennedy International Airport at Terminal 8.
How many American Airlines AA9800 flights are operated a week?
1 flights per week. The Flight American Airlines AA9800 is operated on Sunday.
