American Airlines AA9675 Flight Status Today

Domestic flight American Airlines AA9675 takes off from Albany (ALB) United States to Cleveland (CLE) United States. It's operated by American Airlines. The plane leaves Albany International Airport at 15:30 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 17:00 America/New_York. The flight will last about 1 hours 30 minutes.

AA9675 - AAL9675 American Airlines (AA)
ALB Albany United States
Flight ALB to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Albany International Airport
IATA: ALBICAO: KALB
Scheduled 15:30
None B9
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:00
None C9
AA9675 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 680 kms / 423 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: F-KDMN1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Albany: Monday 2026-01-26 12:15 PM
  • Current Time in Cleveland: Monday 2026-01-26 12:15 PM

American Airlines Flight AA9675 FAQs

What is the scheduled flight duration for American Airlines AA9675 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 680 km (423 miles).

What type of aircraft is used for the American Airlines AA9675 flight?

All American Airlines AA9675 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

How many American Airlines AA9675 flights are operated a week?

1 flights per week. The Flight American Airlines AA9675 is operated on Friday.