American Airlines AA9505 Flight Status Today

Domestic flight American Airlines AA9505 takes off from Cleveland (CLE) United States to Boston (BOS) United States. It's operated by American Airlines. The plane leaves Cleveland Hopkins International Airport at 17:50 America/New_York. The flight is expected to land at Logan International Airport at 19:34 America/New_York. The flight will last about 1 hours 44 minutes.

AA9505 - AAL9505 American Airlines (AA)
CLE Cleveland United States
Flight CLE to BOS
BOS Boston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-April-2020
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:50
None C6
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 19:34
C C33
AA9505 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 44 minutes
  • Flight Distance: 903 kms / 561 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 190
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2025-12-28 17:52 PM
  • Current Time in Boston: Sunday 2025-12-28 17:52 PM

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Delta DL5684
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11:33

American Airlines Flight AA9505 FAQs

What is the scheduled flight duration for American Airlines AA9505 flight?

On average, nonstop flight takes 1 hour(s) 44 minutes, with the flight distance of 903 km (561 miles).

What type of aircraft is used for the American Airlines AA9505 flight?

All American Airlines AA9505 flights are operated using Embraer 190 aircraft.

Which terminal the flight American Airlines AA9505 is arriving at?

Flight American Airlines AA9505 arrives in Logan International Airport at Terminal C.