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American Airlines AA9455 Flight Status Today
Domestic flight American Airlines AA9455 takes off from Buffalo (BUF) United States to New York (JFK) United States. It's operated by American Airlines. The plane leaves Buffalo Niagara International Airport at 16:33 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 18:00 America/New_York. The flight will last about 1 hours 27 minutes.
- Type: Domestic Flight
- Flight Duration: 1 hours 27 minutes
- Flight Distance: 483 kms / 300 miles
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Embraer 190
- Callsign: None
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Buffalo: Sunday 2026-01-18 01:41 AM
- Current Time in New York: Sunday 2026-01-18 01:41 AM
Flight routes similar to American Airlines AA9455
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
TK8950 Turkish Airlines |
18/01/2026 07:00 |
1 hours 29 minutes 08:29 |
|
TK8566 Turkish Airlines |
18/01/2026 19:45 |
1 hours 35 minutes 21:20 |
|
B62001 JetBlue Airways |
18/01/2026 07:00 |
1 hours 29 minutes 08:29 |
|
AM3434 Aeromexico |
18/01/2026 11:51 |
1 hours 35 minutes 13:26 |
|
AF3072 Air France |
18/01/2026 15:38 |
1 hours 47 minutes 17:25 |
|
9E5426 Endeavor Air |
18/01/2026 11:51 |
1 hours 35 minutes 13:26 |
|
VS4614 Virgin Atlantic |
18/01/2026 19:42 |
1 hours 50 minutes 21:32 |
|
LA7050 LATAM Airlines |
18/01/2026 15:43 |
1 hours 34 minutes 17:30 |
American Airlines Flight AA9455 FAQs
What is the scheduled flight duration for American Airlines AA9455 flight?
On average, nonstop flight takes 1 hour(s) 27 minutes, with the flight distance of 483 km (300 miles).
What type of aircraft is used for the American Airlines AA9455 flight?
All American Airlines AA9455 flights are operated using Embraer 190 aircraft.
Which terminal the flight American Airlines AA9455 is arriving at?
Flight American Airlines AA9455 arrives in John F. Kennedy International Airport at Terminal 5.
