American Airlines AA9455 Flight Status Today

Domestic flight American Airlines AA9455 takes off from Buffalo (BUF) United States to New York (JFK) United States. It's operated by American Airlines. The plane leaves Buffalo Niagara International Airport at 16:33 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 18:00 America/New_York. The flight will last about 1 hours 27 minutes.

AA9455 - AAL9455 American Airlines (AA)
BUF Buffalo United States
Flight BUF to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Buffalo Niagara International Airport
IATA: BUFICAO: KBUF
Scheduled 16:33
None 8
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 18:00
5 None
AA9455 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 27 minutes
  • Flight Distance: 483 kms / 300 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 190
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Buffalo: Saturday 2026-02-07 07:00 AM
  • Current Time in New York: Saturday 2026-02-07 07:00 AM

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American Airlines Flight AA9455 FAQs

What is the scheduled flight duration for American Airlines AA9455 flight?

On average, nonstop flight takes 1 hour(s) 27 minutes, with the flight distance of 483 km (300 miles).

What type of aircraft is used for the American Airlines AA9455 flight?

All American Airlines AA9455 flights are operated using Embraer 190 aircraft.

Which terminal the flight American Airlines AA9455 is arriving at?

Flight American Airlines AA9455 arrives in John F. Kennedy International Airport at Terminal 5.