American Airlines AA7475 Flight Status Today

Domestic flight American Airlines AA7475 takes off from San Diego (SAN) United States to Belgrade (BZN) United States. It's operated by American Airlines. The plane leaves San Diego International Airport at 08:02 America/Los_Angeles. The flight is expected to land at Bozeman Yellowstone International Airport at 12:02 America/Denver. The flight will last about 0 minutes.

AA7475 - AAL7475 American Airlines (AA)
SAN San Diego United States
Flight SAN to BZN
BZN Belgrade United States
Contact Airlines It may not operate on the date requested
Departure San Diego International Airport
IATA: SANICAO: KSAN
Scheduled 08:02
2 48
Arrival Bozeman Yellowstone International Airport
IATA: BZNICAO: KBZN
Scheduled 12:02
None B5
AA7475 Detail
  • Type: Domestic Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 1538 kms / 956 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Embraer 175
  • Callsign: AAL7475
  • Departure Timezone: America/Los_Angeles
  • Arrival Timezone: America/Denver
  • Current Time in San Diego: Saturday 2026-03-28 04:38 AM
  • Current Time in Belgrade: Saturday 2026-03-28 05:38 AM

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American Airlines Flight AA7475 FAQs

What is the scheduled flight duration for American Airlines AA7475 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 1538 km (956 miles).

What type of aircraft is used for the American Airlines AA7475 flight?

All American Airlines AA7475 flights are operated using Embraer 175 aircraft.

How many American Airlines AA7475 flights are operated a week?

6 flights per week. The Flight American Airlines AA7475 is operated on Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.