American Airlines AA4800 Flight Status Today

Domestic flight American Airlines AA4800 takes off from Washington (DCA) United States to Indianapolis (IND) United States. It's operated by American Airlines. The plane leaves Ronald Reagan National Airport at 16:39 America/New_York. The flight is expected to land at Indianapolis International Airport at 18:35 America/Indiana/Indianapolis. The flight will last about 1 hours 56 minutes.

AA4800 - AAL4800 American Airlines (AA)
DCA Washington United States
Flight DCA to IND
IND Indianapolis United States
Contact Airlines It may not operate on the date requested
Departure Ronald Reagan National Airport
IATA: DCAICAO: KDCA
Scheduled 16:39
2 E59
Arrival Indianapolis International Airport
IATA: INDICAO: KIND
Scheduled 18:35
None B14
AA4800 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 56 minutes
  • Flight Distance: 803 kms / 499 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 0 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KMNN1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Indiana/Indianapolis
  • Current Time in Washington: Sunday 2026-01-18 17:34 PM
  • Current Time in Indianapolis: Sunday 2026-01-18 17:34 PM

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American Airlines Flight AA4800 FAQs

What is the scheduled flight duration for American Airlines AA4800 flight?

On average, nonstop flight takes 1 hour(s) 56 minutes, with the flight distance of 803 km (499 miles).

What type of aircraft is used for the American Airlines AA4800 flight?

All American Airlines AA4800 flights are operated using Embraer 175 aircraft.

How many American Airlines AA4800 flights are operated a week?

1 flights per week. The Flight American Airlines AA4800 is operated on Saturday.