American Airlines AA4675 Flight Status Today

Domestic flight American Airlines AA4675 takes off from Jacksonville (JAX) United States to New York (LGA) United States. It's operated by American Airlines. The plane leaves Jacksonville International Airport at 08:05 America/New_York. The flight is expected to land at LaGuardia Airport at 10:25 America/New_York. The flight will last about 2 hours 14 minutes.

AA4675 - AAL4675 American Airlines (AA)
JAX Jacksonville United States
Flight JAX to LGA
LGA New York United States
Contact Airlines It may not operate on the date requested
Departure Jacksonville International Airport
IATA: JAXICAO: KJAX
Scheduled 08:05
None C10
Arrival LaGuardia Airport
IATA: LGAICAO: KLGA
Scheduled 10:25
B 15
AA4675 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 14 minutes
  • Flight Distance: 1341 kms / 833 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KSTL2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Jacksonville: Friday 2026-03-06 08:35 AM
  • Current Time in New York: Friday 2026-03-06 08:35 AM

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American Airlines Flight AA4675 FAQs

What is the scheduled flight duration for American Airlines AA4675 flight?

On average, nonstop flight takes 2 hour(s) 14 minutes, with the flight distance of 1341 km (833 miles).

What type of aircraft is used for the American Airlines AA4675 flight?

All American Airlines AA4675 flights are operated using Embraer 175 aircraft.

Which terminal the flight American Airlines AA4675 is arriving at?

Flight American Airlines AA4675 arrives in LaGuardia Airport at Terminal B.

How many American Airlines AA4675 flights are operated a week?

1 flights per week. The Flight American Airlines AA4675 is operated on Saturday.