American Airlines AA4407 Flight Status Today

Domestic flight American Airlines AA4407 takes off from Cleveland (CLE) United States to New York (LGA) United States. It's operated by American Airlines. The plane leaves Cleveland Hopkins International Airport at 13:48 America/New_York. The flight is expected to land at LaGuardia Airport at 15:30 America/New_York. The flight will last about 1 hours 38 minutes.

AA4407 - AAL4407 American Airlines (AA)
CLE Cleveland United States
Flight CLE to LGA
LGA New York United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 13:48
None C9
Arrival LaGuardia Airport
IATA: LGAICAO: KLGA
Scheduled 15:30
B 30
AA4407 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 38 minutes
  • Flight Distance: 673 kms / 418 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Wednesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KLWB1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Monday 2025-12-29 03:00 AM
  • Current Time in New York: Monday 2025-12-29 03:00 AM

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American Airlines Flight AA4407 FAQs

What is the scheduled flight duration for American Airlines AA4407 flight?

On average, nonstop flight takes 1 hour(s) 38 minutes, with the flight distance of 673 km (418 miles).

What type of aircraft is used for the American Airlines AA4407 flight?

All American Airlines AA4407 flights are operated using Embraer 175 aircraft.

Which terminal the flight American Airlines AA4407 is arriving at?

Flight American Airlines AA4407 arrives in LaGuardia Airport at Terminal B.

How many American Airlines AA4407 flights are operated a week?

1 flights per week. The Flight American Airlines AA4407 is operated on Wednesday.