American Airlines AA4407 Flight Status Today

Domestic flight American Airlines AA4407 takes off from New York (LGA) United States to Cleveland (CLE) United States. It's operated by American Airlines. The plane leaves LaGuardia Airport at 11:10 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 13:02 America/New_York. The flight will last about 1 hours 52 minutes.

AA4407 - AAL4407 American Airlines (AA)
LGA New York United States
Flight LGA to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure LaGuardia Airport
IATA: LGAICAO: KLGA
Scheduled 11:10
B 22
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 13:02
None C5
AA4407 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 52 minutes
  • Flight Distance: 673 kms / 418 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Wednesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 3 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KLWB1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-04-11 06:30 AM
  • Current Time in Cleveland: Saturday 2026-04-11 06:30 AM

Flight routes similar to American Airlines AA4407

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Delta DL5190
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American Airlines Flight AA4407 FAQs

What is the scheduled flight duration for American Airlines AA4407 flight?

On average, nonstop flight takes 1 hour(s) 52 minutes, with the flight distance of 673 km (418 miles).

What type of aircraft is used for the American Airlines AA4407 flight?

All American Airlines AA4407 flights are operated using Embraer 175 aircraft.

How many American Airlines AA4407 flights are operated a week?

1 flights per week. The Flight American Airlines AA4407 is operated on Wednesday.