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American Airlines AA4143 Flight Status Today
Domestic flight American Airlines AA4143 takes off from Jacksonville (JAX) United States to Tallahassee (TLH) United States. It's operated by American Airlines. The plane leaves Jacksonville International Airport at 19:10 11 January 2026 America/New_York. The flight is expected to land at Tallahassee International Airport at 22:16 11 January 2026 America/New_York. The flight will last about 2 hours 6 minutes.
Current status of AA4143 is Scheduled On time Estimated Depart in 15 hours, 21 minutes
- Type: Domestic Flight
- Code Shares: QF 4361, QR 2550
- Flight Duration: 2 hours 6 minutes
- Flight Distance: 256 kms / 159 miles
- American Airlines
- IATA: AA
- ICAO: AAL
- Operating Days: Tuesday
- Service type: Normal passenger
- Seats: 44
- Freight capacity: 0 tons
- Passenger classes: Economy
- Aircraft: Embraer 175
- Callsign: F-KMHL1
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Jacksonville: Sunday 2026-01-11 03:49 AM
- Current Time in Tallahassee: Sunday 2026-01-11 03:49 AM
American Airlines Flight AA4143 FAQs
What is the scheduled flight duration for American Airlines AA4143 flight?
On average, nonstop flight takes 2 hour(s) 6 minutes, with the flight distance of 256 km (159 miles).
What is the current status of American Airlines AA4143 flight?
The current status of flight American Airlines AA4143 is Scheduled On time.
What type of aircraft is used for the American Airlines AA4143 flight?
All American Airlines AA4143 flights are operated using Embraer 175 aircraft.
How many American Airlines AA4143 flights are operated a week?
1 flights per week. The Flight American Airlines AA4143 is operated on Tuesday.
