American Airlines AA4045 Flight Status Today

Domestic flight American Airlines AA4045 takes off from Savannah (SAV) United States to Miami (MIA) United States. It's operated by American Airlines. The plane leaves Savannah/Hilton Head Airport at 11:33 America/New_York. The flight is expected to land at Miami International Airport at 13:06 America/New_York. The flight will last about 1 hours 33 minutes.

AA4045 - AAL4045 American Airlines (AA)
SAV Savannah United States
Flight SAV to MIA
MIA Miami United States
Contact Airlines It may not operate on the date requested
Departure Savannah/Hilton Head Airport
IATA: SAVICAO: KSAV
Scheduled 11:33
None 10
Arrival Miami International Airport
IATA: MIAICAO: KMIA
Scheduled 13:06
N D53
AA4045 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 709 kms / 440 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Saturday
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 0 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: F-KMHL1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Savannah: Sunday 2026-03-01 08:09 AM
  • Current Time in Miami: Sunday 2026-03-01 08:09 AM

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American Airlines Flight AA4045 FAQs

What is the scheduled flight duration for American Airlines AA4045 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 709 km (440 miles).

What type of aircraft is used for the American Airlines AA4045 flight?

All American Airlines AA4045 flights are operated using Embraer 175 aircraft.

Which terminal the flight American Airlines AA4045 is arriving at?

Flight American Airlines AA4045 arrives in Miami International Airport at Terminal N.

How many American Airlines AA4045 flights are operated a week?

1 flights per week. The Flight American Airlines AA4045 is operated on Saturday.