American Airlines AA2045 Flight Status Today

Domestic flight American Airlines AA2045 takes off from New York (JFK) United States to Charlotte (CLT) United States. It's operated by American Airlines. The plane leaves John F. Kennedy International Airport at 06:30 America/New_York. The flight is expected to land at Charlotte Douglas International Airport at 08:40 America/New_York. The flight will last about 1 hours 50 minutes.

AA2045 - AAL2045 American Airlines (AA)
JFK New York United States
Flight JFK to CLT
CLT Charlotte United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 06:30
8 2
Arrival Charlotte Douglas International Airport
IATA: CLTICAO: KCLT
Scheduled 08:40
None D2
AA2045 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 50 minutes
  • Flight Distance: 870 kms / 540 miles
Airline
  • American Airlines
  • IATA: AA
  • ICAO: AAL
  • Operating Days: Wednesday
Passenger Services
  • Service type: Normal passenger
  • Seats: 187
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
  • Callsign: F-KGLS2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Saturday 2026-02-14 16:30 PM
  • Current Time in Charlotte: Saturday 2026-02-14 16:30 PM

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American Airlines Flight AA2045 FAQs

What is the scheduled flight duration for American Airlines AA2045 flight?

On average, nonstop flight takes 1 hour(s) 50 minutes, with the flight distance of 870 km (540 miles).

What type of aircraft is used for the American Airlines AA2045 flight?

All American Airlines AA2045 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.

How many American Airlines AA2045 flights are operated a week?

1 flights per week. The Flight American Airlines AA2045 is operated on Wednesday.