Azimuth Airlines A49410 Flight Status Today

International flight Azimuth Airlines A49410 takes off from Moscow (VKO) Russia to Dushanbe (DYU) Tajikistan. It's operated by Azimuth Airlines. The plane leaves Vnukovo Airport at 03:00 Europe/Moscow. The flight is expected to land at Dushanbe Airport at 05:00 Asia/Dushanbe. The flight will last about 4 hours 7 minutes.

A49410 - AZO9410 Azimuth Airlines (A4)
VKO Moscow Russia
Flight VKO to DYU
DYU Dushanbe Tajikistan
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-March-2023
Departure Vnukovo Airport
IATA: VKOICAO: UUWW
Scheduled 03:00
None None
Arrival Dushanbe Airport
IATA: DYUICAO: UTDD
Scheduled 05:00
None None
A49410 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 7 minutes
  • Flight Distance: 3010 kms / 1870 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Sukhoi Superjet 100-95B
  • Callsign: AZO9410
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Asia/Dushanbe
  • Current Time in Moscow: Wednesday 2025-12-31 03:45 AM
  • Current Time in Dushanbe: Wednesday 2025-12-31 05:45 AM

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Azimuth Airlines Flight A49410 FAQs

What is the scheduled flight duration for Azimuth Airlines A49410 flight?

On average, nonstop flight takes 4 hour(s) 7 minutes, with the flight distance of 3010 km (1870 miles).

What type of aircraft is used for the Azimuth Airlines A49410 flight?

All Azimuth Airlines A49410 flights are operated using Sukhoi Superjet 100-95B aircraft.