Azimuth Airlines A49405 Flight Status Today

International flight Azimuth Airlines A49405 takes off from Dushanbe (DYU) Tajikistan to Moscow (VKO) Russia. It's operated by Azimuth Airlines. The plane leaves Dushanbe Airport at 18:22 Asia/Dushanbe. The flight is expected to land at Vnukovo Airport at None Europe/Moscow. The flight will last about 4 hours 8 minutes.

A49405 - AZO9405 Azimuth Airlines (A4)
DYU Dushanbe Tajikistan
Flight DYU to VKO
VKO Moscow Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Dushanbe Airport
IATA: DYUICAO: UTDD
Scheduled 18:22
None None
Arrival Vnukovo Airport
IATA: VKOICAO: UUWW
Scheduled None
None None
A49405 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 8 minutes
  • Flight Distance: 3010 kms / 1870 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Sukhoi Superjet 100-95B
  • Callsign: AZO9405
  • Departure Timezone: Asia/Dushanbe
  • Arrival Timezone: Europe/Moscow
  • Current Time in Dushanbe: Wednesday 2025-12-31 05:43 AM
  • Current Time in Moscow: Wednesday 2025-12-31 03:43 AM

Flight routes similar to Azimuth Airlines A49405

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UTair UT802
UTair 		31/12/2025
17:00 		4 hours 40 minutes
19:40
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UTair 		31/12/2025
06:30 		4 hours 40 minutes
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Azimuth Airlines Flight A49405 FAQs

What is the scheduled flight duration for Azimuth Airlines A49405 flight?

On average, nonstop flight takes 4 hour(s) 8 minutes, with the flight distance of 3010 km (1870 miles).

What type of aircraft is used for the Azimuth Airlines A49405 flight?

All Azimuth Airlines A49405 flights are operated using Sukhoi Superjet 100-95B aircraft.