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Azimuth Airlines A49208 flight status now
A49208 - AZO9208
Azimuth Airlines (A4)
OVS
Sovetsky Russia
AER
Sochi Russia
Contact Airlines
It may not operate on the date requested
A49208 Detail
- Type: Domestic Flight
- Flight Duration: 4 hours 1 minutes
- Flight Distance: 2530 kms / 1572 miles
Airline
- Azimuth Airlines
- IATA: A4
- ICAO: AZO
- Operating Days: Thursday
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: Sukhoi Superjet 100-95LR
- Callsign: AZO9208
- Departure Timezone: Asia/Yekaterinburg
- Arrival Timezone: Europe/Moscow
- Current Time in Sovetsky: Tuesday 2025-11-18 13:11 PM
- Current Time in Sochi: Tuesday 2025-11-18 11:11 AM
Domestic flight Azimuth Airlines A49208 takes off from Sovetsky (OVS) Russia to Sochi (AER) Russia. It's operated by Azimuth Airlines. The plane leaves Sovetsky Airport at 14:39 Asia/Yekaterinburg. The flight is expected to land at Sochi International Airport at None Europe/Moscow. The flight will last about 4 hours 1 minutes.
Similar flight route from Sovetsky (OVS) to Sochi (AER)
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
WZ4512 Red Wings |
18/11/2025 10:00 |
4 hours 35 minutes 12:35 |
Frequently asked questions, answered
How long is the flight from Sovetsky to Sochi?
On average, nonstop flight takes 4 hour(s) 1 minutes, with the flight distance of 2530 km (1572 miles).
What type of aircraft is used for the Azimuth Airlines A49208 flight?
All Azimuth Airlines A49208 flights are operated using Sukhoi Superjet 100-95LR aircraft.
How many Azimuth Airlines A49208 flights are operated a week?
1 flights per week. The Flight Azimuth Airlines A49208 is operated on Thursday.
