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Azimuth Airlines A49064 flight status now
- Type: International Flight
- Flight Duration: 4 hours 5 minutes
- Flight Distance: 2665 kms / 1656 miles
- Azimuth Airlines
- IATA: A4
- ICAO: AZO
- Operating Days: Tuesday, Thursday, Saturday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: Sukhoi Superjet 100-95
- Callsign: F-UATG2
- Departure Timezone: Asia/Tashkent
- Arrival Timezone: Europe/Moscow
- Current Time in Bukhara: Wednesday 2025-11-19 04:59 AM
- Current Time in Moscow: Wednesday 2025-11-19 02:59 AM
International flight Azimuth Airlines A49064 takes off from Bukhara (BHK) Uzbekistan to Moscow (VKO) Russia. It's operated by Azimuth Airlines. The plane leaves Bukhara Airport at 04:40 Asia/Tashkent. The flight is expected to land at Vnukovo Airport at 06:45 Europe/Moscow. The flight will last about 4 hours 5 minutes.
Similar flight route from Bukhara (BHK) to Moscow (VKO)
Frequently asked questions, answered
How long is the flight from Bukhara to Moscow?
On average, nonstop flight takes 4 hour(s) 5 minutes, with the flight distance of 2665 km (1656 miles).
What type of aircraft is used for the Azimuth Airlines A49064 flight?
All Azimuth Airlines A49064 flights are operated using Sukhoi Superjet 100-95 aircraft.
Which terminal the flight Azimuth Airlines A49064 is arriving at?
Flight Azimuth Airlines A49064 arrives in Vnukovo Airport at Terminal A.
How many Azimuth Airlines A49064 flights are operated a week?
3 flights per week. The Flight Azimuth Airlines A49064 is operated on Tuesday, Thursday, Saturday.
