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Azimuth Airlines A49047 Flight Status Today
International flight Azimuth Airlines A49047 takes off from Moscow (VKO) Russia to Bukhara (BHK) Uzbekistan. It's operated by Azimuth Airlines. The plane leaves Vnukovo Airport at 03:00 Europe/Moscow. The flight is expected to land at Bukhara Airport at 05:00 Asia/Tashkent. The flight will last about 3 hours 47 minutes.
A49047 - AZO9047
Azimuth Airlines (A4)
VKO
Moscow Russia
BHK
Bukhara Uzbekistan
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on 18-March-2022
A49047 Detail
- Type: International Flight
- Flight Duration: 3 hours 47 minutes
- Flight Distance: 2665 kms / 1656 miles
Airline
- Azimuth Airlines
- IATA: A4
- ICAO: AZO
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: SU95
- Callsign: AZO9047
- Departure Timezone: Europe/Moscow
- Arrival Timezone: Asia/Tashkent
- Current Time in Moscow: Wednesday 2025-12-31 23:19 PM
- Current Time in Bukhara: Thursday 2026-01-01 01:19 AM
Flight routes similar to Azimuth Airlines A49047
Azimuth Airlines Flight A49047 FAQs
What is the scheduled flight duration for Azimuth Airlines A49047 flight?
On average, nonstop flight takes 3 hour(s) 47 minutes, with the flight distance of 2665 km (1656 miles).
What type of aircraft is used for the Azimuth Airlines A49047 flight?
All Azimuth Airlines A49047 flights are operated using SU95 aircraft.
