Azimuth Airlines A4749 Flight Status Today

Domestic flight Azimuth Airlines A4749 takes off from Rostov (ROV) Russia to Chelyabinsk (CEK) Russia. It's operated by Azimuth Airlines. The plane leaves Platov International Airport at 00:30 Europe/Moscow. The flight is expected to land at Chelyabinsk International Airport at 05:05 Asia/Yekaterinburg. The flight will last about 2 hours 35 minutes.

A4749 - AZO749 Azimuth Airlines (A4)
ROV Rostov Russia
Flight ROV to CEK
CEK Chelyabinsk Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-January-2022
Departure Platov International Airport
IATA: ROVICAO: URRR
Scheduled 00:30
None None
Arrival Chelyabinsk International Airport
IATA: CEKICAO: USCC
Scheduled 05:05
None None
A4749 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 35 minutes
  • Flight Distance: 1725 kms / 1072 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Asia/Yekaterinburg
  • Current Time in Rostov: Tuesday 2026-01-20 00:20 AM
  • Current Time in Chelyabinsk: Tuesday 2026-01-20 02:20 AM

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Azimuth Airlines Flight A4749 FAQs

What is the scheduled flight duration for Azimuth Airlines A4749 flight?

On average, nonstop flight takes 2 hour(s) 35 minutes, with the flight distance of 1725 km (1072 miles).