Azimuth Airlines A4704 Flight Status Today

Domestic flight Azimuth Airlines A4704 takes off from Saint Petersburg (LED) Russia to Krasnodar (KRR) Russia. It's operated by Azimuth Airlines. The plane leaves Pulkovo Airport at 23:00 Europe/Moscow. The flight is expected to land at Krasnodar International Airport at 01:50 Europe/Moscow. The flight will last about 2 hours 50 minutes.

A4704 - AZO704 Azimuth Airlines (A4)
LED Saint Petersburg Russia
Flight LED to KRR
KRR Krasnodar Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-January-2022
Departure Pulkovo Airport
IATA: LEDICAO: ULLI
Scheduled 23:00
1 None
Arrival Krasnodar International Airport
IATA: KRRICAO: URKK
Scheduled 01:50
None None
A4704 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 50 minutes
  • Flight Distance: 1747 kms / 1085 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Sukhoi Superjet 100-95
  • Callsign: AZO704
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Europe/Moscow
  • Current Time in Saint Petersburg: Thursday 2026-01-01 16:30 PM
  • Current Time in Krasnodar: Thursday 2026-01-01 16:30 PM

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Azimuth Airlines Flight A4704 FAQs

What is the scheduled flight duration for Azimuth Airlines A4704 flight?

On average, nonstop flight takes 2 hour(s) 50 minutes, with the flight distance of 1747 km (1085 miles).

What type of aircraft is used for the Azimuth Airlines A4704 flight?

All Azimuth Airlines A4704 flights are operated using Sukhoi Superjet 100-95 aircraft.