Check your Flight status online
Azimuth Airlines A45008 Flight Status Today
Domestic flight Azimuth Airlines A45008 takes off from Makhachkala (MCX) Russia to Sochi (AER) Russia. It's operated by Azimuth Airlines. The plane leaves Makhachkala Airport at 21:20 28 February 2026 Europe/Moscow. The flight is expected to land at Sochi International Airport at 22:45 28 February 2026 Europe/Moscow. The flight will last about 1 hours 25 minutes.
Current status of A45008 is Scheduled On time Expected Depart in 1 hour, 20 minutes
- Type: Domestic Flight
- Flight Duration: 1 hours 25 minutes
- Flight Distance: 631 kms / 392 miles
- Azimuth Airlines
- IATA: A4
- ICAO: AZO
- Operating Days: Monday, Thursday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Sukhoi Superjet 100-95
- Callsign: N/A
- Departure Timezone: Europe/Moscow
- Arrival Timezone: Europe/Moscow
- Current Time in Makhachkala: Saturday 2026-02-28 20:00 PM
- Current Time in Sochi: Saturday 2026-02-28 20:00 PM
Azimuth Airlines Flight A45008 FAQs
What is the scheduled flight duration for Azimuth Airlines A45008 flight?
On average, nonstop flight takes 1 hour(s) 25 minutes, with the flight distance of 631 km (392 miles).
What is the current status of Azimuth Airlines A45008 flight?
The current status of flight Azimuth Airlines A45008 is Scheduled On time.
What type of aircraft is used for the Azimuth Airlines A45008 flight?
All Azimuth Airlines A45008 flights are operated using Sukhoi Superjet 100-95 aircraft.
How many Azimuth Airlines A45008 flights are operated a week?
3 flights per week. The Flight Azimuth Airlines A45008 is operated on Monday, Thursday, Sunday.
