Azimuth Airlines A45006 Flight Status Today

Domestic flight Azimuth Airlines A45006 takes off from Yaroslavl (IAR) Russia to Sochi (AER) Russia. It's operated by Azimuth Airlines. The plane leaves Tunoshna Airport at 20:50 Europe/Moscow. The flight is expected to land at Sochi International Airport at 00:10 Europe/Moscow. The flight will last about 3 hours 20 minutes.

A45006 - AZO5006 Azimuth Airlines (A4)
IAR Yaroslavl Russia
Flight IAR to AER
AER Sochi Russia
Contact Airlines It may not operate on the date requested
Departure Tunoshna Airport
IATA: IARICAO: UUDL
Scheduled 20:50
None None
Arrival Sochi International Airport
IATA: AERICAO: URSS
Scheduled 00:10
None None
A45006 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 20 minutes
  • Flight Distance: 1570 kms / 975 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: Tuesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Sukhoi Superjet 100-95
  • Callsign: None
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Europe/Moscow
  • Current Time in Yaroslavl: Monday 2026-01-19 07:17 AM
  • Current Time in Sochi: Monday 2026-01-19 07:17 AM

Flight routes similar to Azimuth Airlines A45006

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Azimuth Airlines Flight A45006 FAQs

What is the scheduled flight duration for Azimuth Airlines A45006 flight?

On average, nonstop flight takes 3 hour(s) 20 minutes, with the flight distance of 1570 km (975 miles).

What type of aircraft is used for the Azimuth Airlines A45006 flight?

All Azimuth Airlines A45006 flights are operated using Sukhoi Superjet 100-95 aircraft.

How many Azimuth Airlines A45006 flights are operated a week?

1 flights per week. The Flight Azimuth Airlines A45006 is operated on Tuesday.