Azimuth Airlines A44405 Flight Status Today

International flight Azimuth Airlines A44405 takes off from Moscow (VKO) Russia to Simferopol (SIP) Ukraine. It's operated by Azimuth Airlines. The plane leaves Vnukovo Airport at 11:00 A Europe/Moscow. The flight is expected to land at Simferopol International Airport at 1:30 PM Europe/Kiev. The flight will last about 3 hours 30 minutes.

A44405 - AZO4405 Azimuth Airlines (A4)
VKO Moscow Russia
Flight VKO to SIP
SIP Simferopol Ukraine
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Vnukovo Airport
IATA: VKOICAO: UUWW
Scheduled 11:00 A
A 10
Arrival Simferopol International Airport
IATA: SIPICAO: UKFF
Scheduled 1:30 PM
A44405 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 30 minutes
  • Flight Distance: 1200 kms / 746 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 98
  • Freight capacity: 4.4 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: SU9
  • Callsign: MUT405
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Europe/Kiev
  • Current Time in Moscow: Wednesday 2026-01-21 09:42 AM
  • Current Time in Simferopol: Wednesday 2026-01-21 08:42 AM

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None

Azimuth Airlines Flight A44405 FAQs

What is the scheduled flight duration for Azimuth Airlines A44405 flight?

On average, nonstop flight takes 3 hour(s) 30 minutes, with the flight distance of 1200 km (746 miles).

What type of aircraft is used for the Azimuth Airlines A44405 flight?

All Azimuth Airlines A44405 flights are operated using SU9 aircraft.