Azimuth Airlines A4155 Flight Status Today

Domestic flight Azimuth Airlines A4155 takes off from San Andres Island (ADZ) Colombia to Bogota (BOG) Colombia. It's operated by Azimuth Airlines. The plane leaves Gustavo Rojas Pinilla Airport at 20:14 America/Bogota. The flight is expected to land at El Dorado International Airport at 22:09 America/Bogota. The flight will last about 1 hours 55 minutes.

A4155 - AZO155 Azimuth Airlines (A4)
ADZ San Andres Island Colombia
Flight ADZ to BOG
BOG Bogota Colombia
Contact Airlines It may not operate on the date requested
Departure Gustavo Rojas Pinilla Airport
IATA: ADZICAO: SKSP
Scheduled 20:14
None None
Arrival El Dorado International Airport
IATA: BOGICAO: SKBO
Scheduled 22:09
None None
A4155 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 55 minutes
  • Flight Distance: 1205 kms / 749 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: Wednesday, Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-301(BDSF)
  • Callsign: KRE155
  • Departure Timezone: America/Bogota
  • Arrival Timezone: America/Bogota
  • Current Time in San Andres Island: Saturday 2026-02-07 19:15 PM
  • Current Time in Bogota: Saturday 2026-02-07 19:15 PM

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Azimuth Airlines Flight A4155 FAQs

What is the scheduled flight duration for Azimuth Airlines A4155 flight?

On average, nonstop flight takes 1 hour(s) 55 minutes, with the flight distance of 1205 km (749 miles).

What type of aircraft is used for the Azimuth Airlines A4155 flight?

All Azimuth Airlines A4155 flights are operated using Boeing 737-301(BDSF) aircraft.

How many Azimuth Airlines A4155 flights are operated a week?

2 flights per week. The Flight Azimuth Airlines A4155 is operated on Wednesday, Friday.