Azimuth Airlines A4145 Flight Status Today

Domestic flight Azimuth Airlines A4145 takes off from Medellin (MDE) Colombia to Bogota (BOG) Colombia. It's operated by Azimuth Airlines. The plane leaves Jose Maria Cordova International Airport at 01:04 America/Bogota. The flight is expected to land at El Dorado International Airport at 01:30 America/Bogota. The flight will last about 25 minutes.

A4145 - AZO145 Azimuth Airlines (A4)
MDE Medellin Colombia
Flight MDE to BOG
BOG Bogota Colombia
Contact Airlines It may not operate on the date requested
Departure Jose Maria Cordova International Airport
IATA: MDEICAO: SKRG
Scheduled 01:04
None None
Arrival El Dorado International Airport
IATA: BOGICAO: SKBO
Scheduled 01:30
None None
A4145 Detail
  • Type: Domestic Flight
  • Flight Duration: 25 minutes
  • Flight Distance: 216 kms / 134 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: Tuesday, Wednesday, Thursday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-301(BDSF)
  • Callsign: KRE145
  • Departure Timezone: America/Bogota
  • Arrival Timezone: America/Bogota
  • Current Time in Medellin: Sunday 2025-12-28 19:25 PM
  • Current Time in Bogota: Sunday 2025-12-28 19:25 PM

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Azimuth Airlines Flight A4145 FAQs

What is the scheduled flight duration for Azimuth Airlines A4145 flight?

On average, nonstop flight takes 25 minutes, with the flight distance of 216 km (134 miles).

What type of aircraft is used for the Azimuth Airlines A4145 flight?

All Azimuth Airlines A4145 flights are operated using Boeing 737-301(BDSF) aircraft.

How many Azimuth Airlines A4145 flights are operated a week?

4 flights per week. The Flight Azimuth Airlines A4145 is operated on Tuesday, Wednesday, Thursday, Saturday.