Azimuth Airlines A4140 Flight Status Today

Domestic flight Azimuth Airlines A4140 takes off from Bogota (BOG) Colombia to Barranquilla (BAQ) Colombia. It's operated by Azimuth Airlines. The plane leaves El Dorado International Airport at 00:04 America/Bogota. The flight is expected to land at Ernesto Cortissoz International Airport at 01:05 America/Bogota. The flight will last about 1 hours 1 minutes.

A4140 - AZO140 Azimuth Airlines (A4)
BOG Bogota Colombia
Flight BOG to BAQ
BAQ Barranquilla Colombia
Contact Airlines It may not operate on the date requested
Departure El Dorado International Airport
IATA: BOGICAO: SKBO
Scheduled 00:04
None None
Arrival Ernesto Cortissoz International Airport
IATA: BAQICAO: SKBQ
Scheduled 01:05
None None
A4140 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 1 minutes
  • Flight Distance: 688 kms / 428 miles
Airline
  • Azimuth Airlines
  • IATA: A4
  • ICAO: AZO
  • Operating Days: Monday, Tuesday, Thursday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 727-223(A)(F)
  • Callsign: KRE140
  • Departure Timezone: America/Bogota
  • Arrival Timezone: America/Bogota
  • Current Time in Bogota: Saturday 2026-02-07 15:17 PM
  • Current Time in Barranquilla: Saturday 2026-02-07 15:17 PM

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Azimuth Airlines Flight A4140 FAQs

What is the scheduled flight duration for Azimuth Airlines A4140 flight?

On average, nonstop flight takes 1 hour(s) 1 minutes, with the flight distance of 688 km (428 miles).

What type of aircraft is used for the Azimuth Airlines A4140 flight?

All Azimuth Airlines A4140 flights are operated using Boeing 727-223(A)(F) aircraft.

How many Azimuth Airlines A4140 flights are operated a week?

4 flights per week. The Flight Azimuth Airlines A4140 is operated on Monday, Tuesday, Thursday, Saturday.