ATI 8C4443 Flight Status Today

Domestic flight ATI 8C4443 takes off from Lakeland (LAL) United States to Wilmington (ILN) United States. It's operated by ATI. The plane leaves Lakeland Municipal Airport at 00:26 America/New_York. The flight is expected to land at Wilmington Airpark at 02:48 America/New_York. The flight will last about 2 hours 58 minutes.

8C4443 - ATN4443 ATI (8C)
LAL Lakeland United States
Flight LAL to ILN
ILN Wilmington United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-December-2020
Departure Lakeland Municipal Airport
IATA: LALICAO: KLAL
Scheduled 00:26
None None
Arrival Wilmington Airpark
IATA: ILNICAO: KILN
Scheduled 02:48
None None
8C4443 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 58 minutes
  • Flight Distance: 1280 kms / 795 miles
Airline
  • ATI
  • IATA: 8C
  • ICAO: ATN
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 767-300 Passenger
  • Callsign: ATN4443
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Lakeland: Monday 2026-01-19 16:23 PM
  • Current Time in Wilmington: Monday 2026-01-19 16:23 PM

Flight routes similar to ATI 8C4443

Airline Flight no Departure Arrival
ATI 8C3491
ATI 		19/01/2026
13:00 		0 minutes
20:53
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ATI 		19/01/2026
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None

ATI Flight 8C4443 FAQs

What is the scheduled flight duration for ATI 8C4443 flight?

On average, nonstop flight takes 2 hour(s) 58 minutes, with the flight distance of 1280 km (795 miles).

What type of aircraft is used for the ATI 8C4443 flight?

All ATI 8C4443 flights are operated using Boeing 767-300 Passenger aircraft.