EZ Air 7Z9811 Flight Status Today

Domestic flight EZ Air 7Z9811 takes off from Oklahoma City (OKC) United States to Tucson (TUS) United States. It's operated by EZ Air. The plane leaves Will Rogers World Airport at 15:02 America/Chicago. The flight is expected to land at Tucson International Airport at None America/Phoenix. The flight will last about 2 hours 6 minutes.

7Z9811 - EZR9811 EZ Air (7Z)
OKC Oklahoma City United States
Flight OKC to TUS
TUS Tucson United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Will Rogers World Airport
IATA: OKCICAO: KOKC
Scheduled 15:02
None None
Arrival Tucson International Airport
IATA: TUSICAO: KTUS
Scheduled None
None None
7Z9811 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 6 minutes
  • Flight Distance: 1287 kms / 800 miles
Airline
  • EZ Air
  • IATA: 7Z
  • ICAO: EZR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: McDonnell Douglas DC-9-15RC
  • Callsign: AJI9811
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Phoenix
  • Current Time in Oklahoma City: Monday 2026-01-19 16:38 PM
  • Current Time in Tucson: Monday 2026-01-19 15:38 PM

Flight routes similar to EZ Air 7Z9811

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13:45
50 minutes
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EZ Air Flight 7Z9811 FAQs

What is the scheduled flight duration for EZ Air 7Z9811 flight?

On average, nonstop flight takes 2 hour(s) 6 minutes, with the flight distance of 1287 km (800 miles).

What type of aircraft is used for the EZ Air 7Z9811 flight?

All EZ Air 7Z9811 flights are operated using McDonnell Douglas DC-9-15RC aircraft.