EZ Air 7Z9680 Flight Status Today

Domestic flight EZ Air 7Z9680 takes off from Greenville (GSP) United States to Laredo (LRD) United States. It's operated by EZ Air. The plane leaves Greenville-Spartanburg International Airport at 20:23 America/New_York. The flight is expected to land at Laredo International Airport at None America/Chicago. The flight will last about 2 hours 56 minutes.

7Z9680 - EZR9680 EZ Air (7Z)
GSP Greenville United States
Flight GSP to LRD
LRD Laredo United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Greenville-Spartanburg International Airport
IATA: GSPICAO: KGSP
Scheduled 20:23
None None
Arrival Laredo International Airport
IATA: LRDICAO: KLRD
Scheduled None
None None
7Z9680 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 56 minutes
  • Flight Distance: 1830 kms / 1137 miles
Airline
  • EZ Air
  • IATA: 7Z
  • ICAO: EZR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: McDonnell Douglas DC-9-15RC
  • Callsign: AJI9680
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Greenville: Thursday 2026-04-16 14:38 PM
  • Current Time in Laredo: Thursday 2026-04-16 13:38 PM

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EZ Air Flight 7Z9680 FAQs

What is the scheduled flight duration for EZ Air 7Z9680 flight?

On average, nonstop flight takes 2 hour(s) 56 minutes, with the flight distance of 1830 km (1137 miles).

What type of aircraft is used for the EZ Air 7Z9680 flight?

All EZ Air 7Z9680 flights are operated using McDonnell Douglas DC-9-15RC aircraft.