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EZ Air 7Z9040 flight status now
- Type: Domestic Flight
- Flight Duration: 2 hours 26 minutes
- Flight Distance: 2059 kms / 1279 miles
- EZ Air
- IATA: 7Z
- ICAO: EZR
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
- Aircraft: McDonnell Douglas DC-9-15RC
- Callsign: AJI9040
- Departure Timezone: America/Chicago
- Arrival Timezone: America/New_York
- Current Time in Laredo: Tuesday 2025-11-18 02:09 AM
- Current Time in Columbus: Tuesday 2025-11-18 03:09 AM
Domestic flight EZ Air 7Z9040 takes off from Laredo (LRD) United States to Columbus (CMH) United States. It's operated by EZ Air. The plane leaves Laredo International Airport at 07:14 America/Chicago. The flight is expected to land at John Glenn Columbus International Airport at None America/New_York. The flight will last about 2 hours 26 minutes.
Similar flight route from Laredo (LRD) to Columbus (CMH)
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
AJI9442 Ameristar Jet Charter |
18/11/2025 13:00 |
None |
Frequently asked questions, answered
How long is the flight from Laredo to Columbus?
On average, nonstop flight takes 2 hour(s) 26 minutes, with the flight distance of 2059 km (1279 miles).
What type of aircraft is used for the EZ Air 7Z9040 flight?
All EZ Air 7Z9040 flights are operated using McDonnell Douglas DC-9-15RC aircraft.
How many EZ Air 7Z9040 flights are operated a week?
6 flights per week. The Flight EZ Air 7Z9040 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.
