EZ Air 7Z9018 Flight Status Today

Domestic flight EZ Air 7Z9018 takes off from Anniston (ANB) United States to Cleveland (CLE) United States. It's operated by EZ Air. The plane leaves Anniston Regional Airport at 20:58 America/Chicago. The flight is expected to land at Cleveland Hopkins International Airport at None America/New_York. The flight will last about 1 hours 26 minutes.

7Z9018 - EZR9018 EZ Air (7Z)
ANB Anniston United States
Flight ANB to CLE
CLE Cleveland United States
Contact Airlines It may not operate on the date requested
Departure Anniston Regional Airport
IATA: ANBICAO: KANB
Scheduled 20:58
None None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled None
None None
7Z9018 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 26 minutes
  • Flight Distance: 938 kms / 583 miles
Airline
  • EZ Air
  • IATA: 7Z
  • ICAO: EZR
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: McDonnell Douglas DC-9-15RC
  • Callsign: AJI9018
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in Anniston: Wednesday 2025-12-31 23:58 PM
  • Current Time in Cleveland: Thursday 2026-01-01 00:58 AM

EZ Air Flight 7Z9018 FAQs

What is the scheduled flight duration for EZ Air 7Z9018 flight?

On average, nonstop flight takes 1 hour(s) 26 minutes, with the flight distance of 938 km (583 miles).

What type of aircraft is used for the EZ Air 7Z9018 flight?

All EZ Air 7Z9018 flights are operated using McDonnell Douglas DC-9-15RC aircraft.

How many EZ Air 7Z9018 flights are operated a week?

6 flights per week. The Flight EZ Air 7Z9018 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.