Atlas Air 5Y4778 Flight Status Today

Domestic flight Atlas Air 5Y4778 takes off from Lakeland (LAL) United States to Allentown (ABE) United States. It's operated by Atlas Air. The plane leaves Lakeland Municipal Airport at 22:30 America/New_York. The flight is expected to land at Lehigh Valley International Airport at 03:30 America/New_York. The flight will last about 3 hours 4 minutes.

5Y4778 - GTI4778 Atlas Air (5Y)
LAL Lakeland United States
Flight LAL to ABE
ABE Allentown United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 15-August-2021
Departure Lakeland Municipal Airport
IATA: LALICAO: KLAL
Scheduled 22:30
None None
Arrival Lehigh Valley International Airport
IATA: ABEICAO: KABE
Scheduled 03:30
None None
5Y4778 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 4 minutes
  • Flight Distance: 1528 kms / 950 miles
Airline
  • Atlas Air
  • IATA: 5Y
  • ICAO: GTI
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 767-300 Passenger
  • Callsign: GTI4778
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Lakeland: Monday 2026-02-09 19:16 PM
  • Current Time in Allentown: Monday 2026-02-09 19:16 PM

Flight routes similar to Atlas Air 5Y4778

Airline Flight no Departure Arrival
ATI 8C3334
ATI 		09/02/2026
11:50 		0 minutes
None

Atlas Air Flight 5Y4778 FAQs

What is the scheduled flight duration for Atlas Air 5Y4778 flight?

On average, nonstop flight takes 3 hour(s) 4 minutes, with the flight distance of 1528 km (950 miles).

What type of aircraft is used for the Atlas Air 5Y4778 flight?

All Atlas Air 5Y4778 flights are operated using Boeing 767-300 Passenger aircraft.