Gazpromavia 4G4954 Flight Status Today

Domestic flight Gazpromavia 4G4954 takes off from Anapa (AAQ) Russia to Sovetsky (OVS) Russia. It's operated by Gazpromavia. The plane leaves Anapa Airport at 10:30 Europe/Moscow. The flight is expected to land at Sovetsky Airport at 16:20 Asia/Yekaterinburg. The flight will last about 3 hours 35 minutes.

4G4954 - GZP4954 Gazpromavia (4G)
AAQ Anapa Russia
Flight AAQ to OVS
OVS Sovetsky Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Anapa Airport
IATA: AAQICAO: URKA
Scheduled 10:30
Arrival Sovetsky Airport
IATA: OVSICAO: USHS
Scheduled 16:20
4G4954 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 35 minutes
  • Flight Distance: 2493 kms / 1549 miles
Airline
  • Gazpromavia
  • IATA: 4G
  • ICAO: GZP
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 90
  • Freight capacity: 4.4 tons
  • Passenger classes: Economy, Business Class
More Detail
  • Aircraft: SU95
  • Callsign: GZP954
  • Departure Timezone: Europe/Moscow
  • Arrival Timezone: Asia/Yekaterinburg
  • Current Time in Anapa: Tuesday 2026-01-20 19:11 PM
  • Current Time in Sovetsky: Tuesday 2026-01-20 21:11 PM

Gazpromavia Flight 4G4954 FAQs

What is the scheduled flight duration for Gazpromavia 4G4954 flight?

On average, nonstop flight takes 3 hour(s) 35 minutes, with the flight distance of 2493 km (1549 miles).

What type of aircraft is used for the Gazpromavia 4G4954 flight?

All Gazpromavia 4G4954 flights are operated using SU95 aircraft.