Gazpromavia 4G401 Flight Status Today

Domestic flight Gazpromavia 4G401 takes off from Sovetsky (OVS) Russia to Anapa (AAQ) Russia. It's operated by Gazpromavia. The plane leaves Sovetsky Airport at 11:35 Asia/Yekaterinburg. The flight is expected to land at Anapa Airport at 13:20 Europe/Moscow. The flight will last about 60 minutes.

4G401 - GZP401 Gazpromavia (4G)
OVS Sovetsky Russia
Flight OVS to AAQ
AAQ Anapa Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-May-2021
Departure Sovetsky Airport
IATA: OVSICAO: USHS
Scheduled 11:35
None None
Arrival Anapa Airport
IATA: AAQICAO: URKA
Scheduled 13:20
None None
4G401 Detail
  • Type: Domestic Flight
  • Flight Duration: 60 minutes
  • Flight Distance: 2493 kms / 1549 miles
Airline
  • Gazpromavia
  • IATA: 4G
  • ICAO: GZP
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: SU95
  • Callsign: None
  • Departure Timezone: Asia/Yekaterinburg
  • Arrival Timezone: Europe/Moscow
  • Current Time in Sovetsky: Tuesday 2026-01-20 21:00 PM
  • Current Time in Anapa: Tuesday 2026-01-20 19:00 PM

Flight routes similar to Gazpromavia 4G401

Airline Flight no Departure Arrival
Gazpromavia 4G731
Gazpromavia 		20/01/2026
16:25 		3 hours 20 minutes
None

Gazpromavia Flight 4G401 FAQs

What is the scheduled flight duration for Gazpromavia 4G401 flight?

On average, nonstop flight takes 60 minutes, with the flight distance of 2493 km (1549 miles).

What type of aircraft is used for the Gazpromavia 4G401 flight?

All Gazpromavia 4G401 flights are operated using SU95 aircraft.