Allegiant Air G45446 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G45446 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 08:33 America/New_York. The flight is expected to land at Asheville Regional Airport at None America/New_York. The flight will last about 1 hours 13 minutes.

G45446 - AAY5446 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 08:33
None None
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled None
None None
G45446 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 13 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A319-111
  • Callsign: AAY5446
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-05-25 12:20 PM
  • Current Time in Asheville: Monday 2026-05-25 12:20 PM

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Allegiant Air Flight G45446 FAQs

What is the scheduled flight duration for Allegiant Air G45446 flight?

On average, nonstop flight takes 1 hour(s) 13 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G45446 flight?

All Allegiant Air G45446 flights are operated using Airbus A319-111 aircraft.