Allegiant Air G41845 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G41845 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 17:54 America/New_York. The flight is expected to land at Asheville Regional Airport at 19:31 America/New_York. The flight will last about 1 hours 34 minutes.

G41845 - AAY1845 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 17:54
None 10
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 19:31
None None
G41845 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Saturday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320 (sharklets)
  • Callsign: F-KTPA1
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Monday 2026-05-25 13:26 PM
  • Current Time in Asheville: Monday 2026-05-25 13:26 PM

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14:44

Allegiant Air Flight G41845 FAQs

What is the scheduled flight duration for Allegiant Air G41845 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G41845 flight?

All Allegiant Air G41845 flights are operated using Airbus A320 (sharklets) aircraft.

How many Allegiant Air G41845 flights are operated a week?

1 flights per week. The Flight Allegiant Air G41845 is operated on Saturday.