Allegiant Air G41045 Flight Status : Live Tracking & Updates

Domestic flight Allegiant Air G41045 takes off from Saint Petersburg (PIE) United States to Asheville (AVL) United States. It's operated by Allegiant Air. The plane leaves St. Petersburg-Clearwater International Airport at 14:26 America/New_York. The flight is expected to land at Asheville Regional Airport at 16:03 America/New_York. The flight will last about 1 hours 37 minutes.

G41045 - AAY1045 Allegiant Air (G4)
PIE Saint Petersburg United States
Flight PIE to AVL
AVL Asheville United States
Contact Airlines It may not operate on the date requested
Departure St. Petersburg-Clearwater International Airport
IATA: PIEICAO: KPIE
Scheduled 14:26
None 3
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 16:03
None None
G41045 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 37 minutes
  • Flight Distance: 834 kms / 518 miles
Airline
  • Allegiant Air
  • IATA: G4
  • ICAO: AAY
  • Operating Days: Thursday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: F-KCHS2
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Saint Petersburg: Tuesday 2026-05-05 13:51 PM
  • Current Time in Asheville: Tuesday 2026-05-05 13:51 PM

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Allegiant Air Flight G41045 FAQs

What is the scheduled flight duration for Allegiant Air G41045 flight?

On average, nonstop flight takes 1 hour(s) 37 minutes, with the flight distance of 834 km (518 miles).

What type of aircraft is used for the Allegiant Air G41045 flight?

All Allegiant Air G41045 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Allegiant Air G41045 flights are operated a week?

2 flights per week. The Flight Allegiant Air G41045 is operated on Thursday, Sunday.