Southwest Airlines WN1514 Flight Status Today

Domestic flight Southwest Airlines WN1514 takes off from Cleveland (CLE) United States to Baltimore (BWI) United States. It's operated by Southwest Airlines. The plane leaves Cleveland Hopkins International Airport at 17:35 America/New_York. The flight is expected to land at Baltimore/Wash International Thurgood Marshall Airport at 18:55 America/New_York. The flight will last about 1 hours 7 minutes.

WN1514 - SWA1514 Southwest Airlines (WN)
CLE Cleveland United States
Flight CLE to BWI
BWI Baltimore United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:35
None B11
Arrival Baltimore/Wash International Thurgood Marshall Airport
IATA: BWIICAO: KBWI
Scheduled 18:55
None A13
WN1514 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 7 minutes
  • Flight Distance: 504 kms / 313 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 175
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737-700 Passenger (Scimitar Winglets)
  • Callsign: F-KONL3
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Sunday 2026-04-12 15:36 PM
  • Current Time in Baltimore: Sunday 2026-04-12 15:36 PM

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Southwest Airlines Flight WN1514 FAQs

What is the scheduled flight duration for Southwest Airlines WN1514 flight?

On average, nonstop flight takes 1 hour(s) 7 minutes, with the flight distance of 504 km (313 miles).

What type of aircraft is used for the Southwest Airlines WN1514 flight?

All Southwest Airlines WN1514 flights are operated using Boeing 737-700 Passenger (Scimitar Winglets) aircraft.

How many Southwest Airlines WN1514 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN1514 is operated on Sunday.