WestJet WS747 Flight Status : Live Tracking & Updates

Domestic flight WestJet WS747 takes off from Sioux Lookout (YXL) Canada to Sandy Lake (ZSJ) Canada. It's operated by WestJet Airlines. The plane leaves Sioux Lookout Airport at 16:40 America/Winnipeg. The flight is expected to land at Sandy Lake Airport at 17:50 America/Winnipeg. The flight will last about 1 hours 30 minutes.

WS747 - WJA747 WestJet Airlines (WS)
YXL Sioux Lookout Canada
Flight YXL to ZSJ
ZSJ Sandy Lake Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 24-July-2018
Departure Sioux Lookout Airport
IATA: YXLICAO: CYXL
Scheduled 16:40
None None
Arrival Sandy Lake Airport
IATA: ZSJICAO: CZSJ
Scheduled 17:50
None None
WS747 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 337 kms / 210 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/Winnipeg
  • Arrival Timezone: America/Winnipeg
  • Current Time in Sioux Lookout: Thursday 2026-05-07 11:06 AM
  • Current Time in Sandy Lake: Thursday 2026-05-07 11:06 AM

Flight routes similar to WestJet WS747

Airline Flight no Departure Arrival
Bearskin Airlines JV510
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15:10 		0 minutes
16:10
Island Air WP1674
Island Air 		07/05/2026
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13:55
Island Air WP1672
Island Air 		07/05/2026
16:50 		60 minutes
17:50
Island Air WP1678
Island Air 		07/05/2026
12:10 		1 hours 29 minutes
13:10

WestJet Flight WS747 FAQs

What is the scheduled flight duration for WestJet WS747 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 337 km (210 miles).