WestJet WS4510 Flight Status : Live Tracking & Updates

Domestic flight WestJet WS4510 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 10:10 America/Vancouver. The flight is expected to land at Calgary International Airport at 12:11 America/Edmonton. The flight will last about 1 hours 14 minutes.

WS4510 - WJA4510 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-May-2021
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 10:10
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 12:11
None None
WS4510 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 14 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
  • Callsign: None
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Sunday 2026-05-24 17:39 PM
  • Current Time in Calgary: Sunday 2026-05-24 18:39 PM

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WestJet Flight WS4510 FAQs

What is the scheduled flight duration for WestJet WS4510 flight?

On average, nonstop flight takes 1 hour(s) 14 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4510 flight?

All WestJet WS4510 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.