WestJet WS4403 Flight Status : Live Tracking & Updates

Domestic flight WestJet WS4403 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by WestJet Airlines. The plane leaves Kelowna International Airport at 15:45 America/Vancouver. The flight is expected to land at Calgary International Airport at 18:21 America/Edmonton. The flight will last about 1 hours 36 minutes.

WS4403 - WJA4403 WestJet Airlines (WS)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
Contact Airlines It may not operate on the date requested
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 15:45
None 7
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 18:21
None A24
WS4403 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • WestJet Airlines
  • IATA: WS
  • ICAO: WJA
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-700 (winglets) Passenger/BBJ1
  • Callsign: F-CYYC6
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Friday 2026-05-08 12:16 PM
  • Current Time in Calgary: Friday 2026-05-08 13:16 PM

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WestJet Flight WS4403 FAQs

What is the scheduled flight duration for WestJet WS4403 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the WestJet WS4403 flight?

All WestJet WS4403 flights are operated using Boeing 737-700 (winglets) Passenger/BBJ1 aircraft.

How many WestJet WS4403 flights are operated a week?

1 flights per week. The Flight WestJet WS4403 is operated on Monday.