Southwest Airlines WN6210 Flight Status : Live Tracking & Updates

Domestic flight Southwest Airlines WN6210 takes off from Cleveland (CLE) United States to Chicago (MDW) United States. It's operated by Southwest Airlines. The plane leaves Cleveland Hopkins International Airport at 11:10 America/New_York. The flight is expected to land at Chicago Midway International Airport at 11:40 America/Chicago. The flight will last about 1 hours 37 minutes.

WN6210 - SWA6210 Southwest Airlines (WN)
CLE Cleveland United States
Flight CLE to MDW
MDW Chicago United States
Contact Airlines It may not operate on the date requested
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 11:10
None B8
Arrival Chicago Midway International Airport
IATA: MDWICAO: KMDW
Scheduled 11:40
None B24
WN6210 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 37 minutes
  • Flight Distance: 494 kms / 307 miles
Airline
  • Southwest Airlines
  • IATA: WN
  • ICAO: SWA
  • Operating Days: Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 175
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: SWA6210
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Cleveland: Wednesday 2026-05-06 23:15 PM
  • Current Time in Chicago: Wednesday 2026-05-06 22:15 PM

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Southwest Airlines Flight WN6210 FAQs

What is the scheduled flight duration for Southwest Airlines WN6210 flight?

On average, nonstop flight takes 1 hour(s) 37 minutes, with the flight distance of 494 km (307 miles).

What type of aircraft is used for the Southwest Airlines WN6210 flight?

All Southwest Airlines WN6210 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Southwest Airlines WN6210 flights are operated a week?

1 flights per week. The Flight Southwest Airlines WN6210 is operated on Sunday.