JetSuiteX XE4903 Flight Status : Live Tracking & Updates

Domestic flight JetSuiteX XE4903 takes off from Dulles (IAD) United States to Knoxville (TYS) United States. It's operated by JSX. The plane leaves Washington Dulles International Airport at 23:52 America/New_York. The flight is expected to land at McGhee Tyson Airport at None America/New_York. The flight will last about 1 hours 8 minutes.

XE4903 - JSX4903 JSX (XE)
IAD Dulles United States
Flight IAD to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Washington Dulles International Airport
IATA: IADICAO: KIAD
Scheduled 23:52
None None
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled None
None None
XE4903 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 8 minutes
  • Flight Distance: 676 kms / 420 miles
Airline
  • JSX
  • IATA: XE
  • ICAO: JSX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer ERJ-145LR
  • Callsign: UCA4903
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Dulles: Monday 2026-05-25 08:06 AM
  • Current Time in Knoxville: Monday 2026-05-25 08:06 AM

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JetSuiteX Flight XE4903 FAQs

What is the scheduled flight duration for JetSuiteX XE4903 flight?

On average, nonstop flight takes 1 hour(s) 8 minutes, with the flight distance of 676 km (420 miles).

What type of aircraft is used for the JetSuiteX XE4903 flight?

All JetSuiteX XE4903 flights are operated using Embraer ERJ-145LR aircraft.