JetBlue Airways B64800 Flight Status : Live Tracking & Updates

Domestic flight JetBlue Airways B64800 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves John F. Kennedy International Airport at 15:13 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 17:11 America/New_York. The flight will last about 1 hours 40 minutes.

B64800 - JBU4800 JetBlue Airways (B6)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 15:13
8 42
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 17:11
None C11
B64800 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 40 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 175
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Friday 2026-05-22 02:50 AM
  • Current Time in Cleveland: Friday 2026-05-22 02:50 AM

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JetBlue Airways Flight B64800 FAQs

What is the scheduled flight duration for JetBlue Airways B64800 flight?

On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the JetBlue Airways B64800 flight?

All JetBlue Airways B64800 flights are operated using Embraer 175 aircraft.