JetBlue Airways B62058 Flight Status : Live Tracking & Updates

Domestic flight JetBlue Airways B62058 takes off from Fort Lauderdale (FLL) United States to Cleveland (CLE) United States. It's operated by JetBlue Airways. The plane leaves Fort Lauderdale-Hollywood International Airport at 10:00 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 12:50 America/New_York. The flight will last about 2 hours 50 minutes.

B62058 - JBU2058 JetBlue Airways (B6)
FLL Fort Lauderdale United States
Flight FLL to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-April-2021
Departure Fort Lauderdale-Hollywood International Airport
IATA: FLLICAO: KFLL
Scheduled 10:00
3 None
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 12:50
None None
B62058 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 50 minutes
  • Flight Distance: 1709 kms / 1062 miles
Airline
  • JetBlue Airways
  • IATA: B6
  • ICAO: JBU
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: None
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Fort Lauderdale: Thursday 2026-05-07 09:05 AM
  • Current Time in Cleveland: Thursday 2026-05-07 09:05 AM

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JetBlue Airways Flight B62058 FAQs

What is the scheduled flight duration for JetBlue Airways B62058 flight?

On average, nonstop flight takes 2 hour(s) 50 minutes, with the flight distance of 1709 km (1062 miles).