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Amapola HP6048 Flight Status Today
Domestic flight Amapola HP6048 takes off from Houston (IAH) United States to Oklahoma City (OKC) United States. It's operated by Amapola. The plane leaves George Bush Intercontinental Airport at 21:00 America/Chicago. The flight is expected to land at Will Rogers World Airport at 22:35 America/Chicago. The flight will last about 1 hours 35 minutes.
HP6048 - APF6048
Amapola (HP)
IAH
Houston United States
OKC
Oklahoma City United States
NO FLIGHTS IN THE LAST 14 DAYS
Lasted record on
HP6048 Detail
- Type: Domestic Flight
- Flight Duration: 1 hours 35 minutes
- Flight Distance: 636 kms / 395 miles
Airline
- Amapola
- IATA: HP
- ICAO: APF
- Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
- Service type: None
- Seats: None
- Freight capacity: None
- Passenger classes: None
More Detail
- Aircraft: None
- Callsign: None
- Departure Timezone: America/Chicago
- Arrival Timezone: America/Chicago
- Current Time in Houston: Thursday 2026-01-22 05:21 AM
- Current Time in Oklahoma City: Thursday 2026-01-22 05:21 AM
Flight routes similar to Amapola HP6048
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
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|
CM1634 Copa Airlines |
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|
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|
|
CM1635 Copa Airlines |
22/01/2026 14:35 |
1 hours 38 minutes 16:13 |
|
NZ6800 Air New Zealand |
22/01/2026 09:45 |
1 hours 38 minutes 11:23 |
|
|
NZ6804 Air New Zealand |
22/01/2026 19:50 |
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|
UA6122 United Airlines |
22/01/2026 09:45 |
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Amapola Flight HP6048 FAQs
What is the scheduled flight duration for Amapola HP6048 flight?
On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 636 km (395 miles).